b^2+12b+35=

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Solution for b^2+12b+35= equation:


Simplifying
b2 + 12b + 35 = 0

Reorder the terms:
35 + 12b + b2 = 0

Solving
35 + 12b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(7 + b)(5 + b) = 0

Subproblem 1

Set the factor '(7 + b)' equal to zero and attempt to solve: Simplifying 7 + b = 0 Solving 7 + b = 0 Move all terms containing b to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + b = 0 + -7 Combine like terms: 7 + -7 = 0 0 + b = 0 + -7 b = 0 + -7 Combine like terms: 0 + -7 = -7 b = -7 Simplifying b = -7

Subproblem 2

Set the factor '(5 + b)' equal to zero and attempt to solve: Simplifying 5 + b = 0 Solving 5 + b = 0 Move all terms containing b to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + b = 0 + -5 Combine like terms: 5 + -5 = 0 0 + b = 0 + -5 b = 0 + -5 Combine like terms: 0 + -5 = -5 b = -5 Simplifying b = -5

Solution

b = {-7, -5}

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